હવે \(\,\Delta u.\Delta x\,\,\, = \,\,\frac{h}{{4\pi m}}\,\,\,\,\,\,\therefore \,\,\Delta x = \frac{{6.625 \times {{10}^{ - 27}}}}{{4 \times 3.14 \times {{10}^{ - 11}} \times {{10}^{ - 7}}}}\,\, = \,\,5.27 \times {10^{ - 10}}cm\)
$(C= 3 \times 10^8 \,ms^{-1},N_A = 6.02 \times 10^{23} mol^{-1}).$