MCQ
Diagram shows a circuit diagram choose incorrect statement


- A${i_1} = \frac{5}{3}A$
- ✓${i_3} = \frac{5}{3}A$
- C${i_2} = \frac{10}{3}A$
- D$i_4 = 5A$

$\mathrm{i}_{4}=\frac{20}{4}=5 \mathrm{\,A}$
$\mathrm{i}_{1}=\frac{3}{3+6} \times 5=\frac{5}{3} \mathrm{\,A}$
$\mathrm{i}_{2}=\frac{6}{3+6} \times 5=\frac{10}{3} \mathrm{\,A}$
$\mathrm{i}_{3}=\frac{6}{3+6} \times 5=\frac{10}{3} \mathrm{\,A}$
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