MCQ
Difference between maximum and minimum values of $f(x) = x^4e^{-x^2} \ \ \forall x \in R,$  is - 
  • A
    $\frac{4}{e^2} - \frac{2}{e}$
  • B
    $\frac{4}{e} - \frac{2}{e^2}$
  • $\frac{4}{e^2}$
  • D
    $\frac{2}{e}$

Answer

Correct option: C.
$\frac{4}{e^2}$
c
$f^{\prime}(x)=0$ at $x=0, \pm \sqrt{2}$

$f(\mathrm{x})_{\max }=\frac{4}{\mathrm{e}^{2}} ; f(\mathrm{x})_{\min }=0$

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