MCQ
Difference between the greatest and the least values of the function$f (x) = x(ln x - 2)$ on $[1, e^2]$ is
  • A
    $2$
  • $e$
  • C
    $e^2$
  • D
    $1$

Answer

Correct option: B.
$e$
b
$y = x (ln x - 2)$

$y' = x\left( {\frac{1}{x}} \right) + (ln x - 2) = ln x - 1$

$\frac{{dy}}{{dx}}= ln x - 1 = 0$==>$x = e$

now$f (1) = - 2$

        $f (e) = - e$(least)

        $f (e^2) = 0$(greatest)

difference $= 0 - (-e) = e$ Ans. 

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