Question
i. Differentiate between:
a. $BeSO _4$ and $BaSO _4$
b. $Be ( OH )_2$ and $Ba ( OH )_2$
ii. Explain diagonal relationship in the periodic table with the help of example.

Answer

i.
a. $BeSO _4$ is soluble in water whereas $BaSO _4$ is insoluble in water.
b. $Be ( OH )_2$ is amphoteric in nature and soluble in NaOH whereas $Ba ( OH )_2$ is strong base and soluble in water.
ii. Diagonal relationship: The resemblance of element of 2 nd period with diagonally situated element of 3 rd period is called diagonal relationship. It is due to similar charge/ radius ratio, i.e., same polarizing power, e.g., Li resembles with Mg .

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