Maharashtra BoardEnglish MediumSTD 11 ScienceMathsDifferentiation1 Mark
Question
Differentiate the following w.r.t. x :
$y =x^{\frac{4}{3}}+e^x-\sin x$
✓
Answer
$ y=x^{\frac{4}{3}}+ e ^x-\sin x $ Differentiating w.r.t. $x$, we get $ \begin{aligned} \frac{ d y}{ d x} & =\frac{ d }{ d x}\left(x^{\frac{4}{3}}+ e ^x-\sin x\right) \\ \frac{ d y}{ d x} & =\frac{ d }{ d x}\left(x^{\frac{4}{3}}\right)+\frac{ d }{ d x}\left( e ^x\right)-\frac{ d }{ d x}(\sin x) \\ & =\frac{4}{3} x^{\frac{4}{3}-1}+ e ^x-\cos x \\ & =\frac{4}{3} x^{\frac{1}{3}}+ e ^x-\cos x \end{aligned} $
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