Question
Discuss the statement pattern, using truth table : $\sim(\sim p \wedge \sim q) \vee q$
Consider the statement pattern: ∼ (∼ p ∧ ∼ q) ∨ q
Thus the truth table of the given logical statement: ~(~p ∧ ~q) ∨ q
| P | q | $\sim p$ | $\sim q$ | $\sim p \wedge \sim q$ | $\sim(\sim p$$\wedge \sim q)$ | $\sim(\sim p$$\wedge \sim q) \vee q$ |
| T | T | F | F | F | T | T |
| T | F | F | T | F | T | T |
| F | T | T | F | F | T | T |
| F | F | T | T | T | F | F |
The above statement is contingency.
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