Displacement is given by x=5+10 t+5 t^2. Find the value of instan… - Vidyadip

Question

Displacement is given by $x=5+10 t+5 t^2$. Find the value of instantaneous acceleration.

✓

Answer

Instantaneous acceleration $(a)=\frac{d^2 x}{d t^2}$$
\frac{d x}{d t}=0+10 \times 1+5 \times 2 t=10+10 t$
$

\therefore \quad \frac{d^2 x}{d t^2}=0+10 \times 1=10

$
Instantaneous acceleration
$

(a)=10

$

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