If the distance covered by an object is directly proportional to time, then we can say that the object :
- Amoves with zero velocity
- Bmoving at a constant speed
- Cacceleration is constant
- ✓has the same velocity
Answer: D.
View full solution →Question types
PART - 1 CH - 2 Motion in a Straight Line question types
104 questions across 8 question groups — pick any mix to generate a Physics paper with step-by-step answer keys.
104
Questions
8
Question groups
5
Question types
01
M.C.Q (1 Marks)
17 Q→02Fill In The Blanks[1 Marks ]
9 Q→031 Marks Question
40 Q→042 Marks Questions
10 Q→053 Marks Question
11 Q→065 Marks Questions
5 Q→07True False[1 Marks ]
10 Q→08Match the following.
2 Q→Sample Questions
PART - 1 CH - 2 Motion in a Straight Line questions
One sample from each question group in this chapter. Select any group above to see the full set with answer keys.
When an object covers equal distances in equal time intervals, then its speed is:
- Aslow motion
- Baccelerated pace
- Cuneven motion
- ✓uneven motion
Answer: D.
View full solution →When a body thrown vertically upward from the earth's surface is at its maximum height, then its :
- Avelocity is maximum
- Bacceleration is zero
- Cacceleration is maximum
- ✓velocity is zero
Answer: D.
View full solution →A piece of stone is thrown into the air. Acceleration of stone :
- Awill always be upwards
- ✓will always be downwards
- CIt will be upwards in upward journey and downwards in downward journey.
- DIt will be downwards in upward journey and upwards in downward journey.
Answer: B.
View full solution →If the displacement of an object is directly proportional to the square of time, then the speed of the object is :
- ✓with uniform acceleration
- Bdue to unequal acceleration
- Cat uniform speed
- Dunequal acceleration but uniform speed
Answer: A.
View full solution →The rate of change of velocity is called ................ .
The slope of the velocity-time graph shows ................ .
A ball thrown vertically upwards from the earth's surface. After reaching a height, it returns to the earth after some time, then its distance will be ................ and displacement will be ................ .
Time-displacement graph is a straight line parallel to the time axis. The values of velocity and acceleration will be ................ .
The decreasing rate of velocity with time is called ................ .
Do the two diagrams given below show the same type of motion or not? Write the name of the motion of the particle.
What do you understand by positive and negative time?
The displacement time diagram of a body is shown in the figure. What does the curve show for $t<0$ and $t>0$ ?
View full solution →Two objects are given, whose initial conditions are different but the relative velocities is zero. Draw the position time diagram for the corners.
Can the relative velocity of one moving object be zero compared to another moving object? Give any example.
In the given figure the time-acceleration graph of an object moving in a straight line is given. Determined from graph :(i) Average acceleration in the first 20 sec.(ii) From what time tell what time the force acts on the object?
The particle position in one-dimensional motion is
$
x=\left(3+4 t-t^2\right) \text { meter }
$
Draw the displacement velocity diagram for this motion from the time interval $t=0 sec$ to $t=4 sec$.
View full solution →$
x=\left(3+4 t-t^2\right) \text { meter }
$
Draw the displacement velocity diagram for this motion from the time interval $t=0 sec$ to $t=4 sec$.
If a person throw a ball up and catches it again after 8 sec . then tell :
(a) With what velocity was the ball thrown up?
(b) At what height will the velocity of the ball be zero?
(a) With what velocity was the ball thrown up?
(b) At what height will the velocity of the ball be zero?
If the initial velocity of a particle is $u$ and the acceleration in the same direction changes with time as $\alpha t$, then what will be the velocity at time $t$ ?
View full solution →The displacement of an object changes with time according to $s=t^3-6 t^2+3 t+4$, then the acceleration of the object at instant is zero. What is its velocity?
View full solution →Q. 13. Draw a time graph for a vehicle from the time-velocity graph given in the attached figure.
In one-dimensional motion the velocity of a particle depends on time in the following manner :
$
v=(5 t+7) m / s
$
If the particle is at the origin at $t=0$, then what will be the position of the particle at $t=2 sec$ ?
View full solution →$
v=(5 t+7) m / s
$
If the particle is at the origin at $t=0$, then what will be the position of the particle at $t=2 sec$ ?
An object falling freely from above is in the last second its total height crosses the division of 16 / 25 then find :
(i) Total height, (ii) Time of fall.
(i) Total height, (ii) Time of fall.
A train start moving from rest and its speed increases with uniform acceleration for 10 sec . At the end of 5 sec . its speed become $54 km /$ hour.
(a) Find the acceleration of the train.
(b) What will be its speed after 10 sec ?
(c) How much distance will the train travel in 10 sec?
(d) How much distance did the train cover in the seventh and tenth second respectively?
View full solution →(a) Find the acceleration of the train.
(b) What will be its speed after 10 sec ?
(c) How much distance will the train travel in 10 sec?
(d) How much distance did the train cover in the seventh and tenth second respectively?
Position $x$, time of particle moving in onedimensional motion depends on as follows :
$x=5+5 t-t^2$
(All quantities are in SI units) For this motion draw (i) displacement-time (ii) Velocity-time (iii) Acceleration-time graphs for the time interval $t=0 sec$ to $t=6 sec$ and describe the motion.
View full solution →$x=5+5 t-t^2$
(All quantities are in SI units) For this motion draw (i) displacement-time (ii) Velocity-time (iii) Acceleration-time graphs for the time interval $t=0 sec$ to $t=6 sec$ and describe the motion.
Prove that the distance covered by a uniformly accelerated body in $n ^{\text {th }}$ second
$
s_n=u+\frac{1}{2} a(2 n-1)
$
View full solution →$
s_n=u+\frac{1}{2} a(2 n-1)
$
Using mathematical methods and algorithms, derive kinetic equations for uniformly accelerated motion
Derive the equations of an object moving with uniform acceleration by graphical method
Define velocity and acceleration. Draw a velocity time graph for uniformly accelerated motion and prove that the area between the curve of this graph and the time axis is equal to the displacement of the moving object
The instantaneous velocity of a uniformly accelerated object can be zero.
Speedometer of a bus measures the instantaneous speed.
Acceleration in differential form is $a=\frac{d v}{d t}$ and $a=\frac{d^2 x}{d t^2}$.
View full solution →The area of the velocity-time graph is the value of the physical quantity displacement.
In circular motion a body can be accelerated without increasing or decreasing its speed.
| (I) | (II) |
| 1. Acceleration a = dv/dt = | (A) $1: 3$ |
| 2. How to find the acceleration of a moving object? | (B) In one-dimensional motion when the direction of the body does not change |
| 3. If the mutual graph of two quantities is a straight line, then both the quantities are: | (C) By the slope of veloc- ity-time graph |
| 4. The ratio of the distances covered by a freely falling object in its first and second second is | (D) Directly Proportional |
| 5. In which position of the body, the value of displacement is equal to the distance travelled by the body? | (E)$\tan \theta$ |
| (I) | (II) |
| 1. For a circular path, if an object moves from A and comes back to A, what will be the value of displacement? | (A) displacement |
| 2. When a body moves in a straight line with a constant velocity in the same direction, then what will be the value of acceleration of the body? | (B) $\tan \theta$ |
| 3. In case of unequal velocity, the displacement and time diagram will have to be made in addition to the straight line. | (C) Zero |
| 4. In the velocity-time graph, the area between the curve and the time axis is equal to which quantity of the body? | (D) Zero |
| 5 Acceleration a = dv/dt = | (E) of any shape |
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