Introduction to Three Dimensional Geometry — MATHS STD 11 Science — Question

1. $\sqrt{27}$

Solution:

Consider the problem,

Let the given points

A(12, 4, 7) and B(10, 5, 3)

So, distance between A and B by distance formula.

$\text{AB}=\sqrt{(10-12)^2+(5-4)^2+(3-7)^2}$

$=\sqrt{(-2)^2+1^2+(-4)^2}$

$=\sqrt{4+1+6}=\sqrt{21}$

So, distance between the points (12, 4, 7) and (10, 5, 3) is $\sqrt{21}\text{ Sq. units}$