MCQ
If $\text{|x}+2|\leq9,$ then:
- A$\text{x}\in(-7,11)$
- B$\text{x}\in[-11,7]$
- C$\text{x}\in(-\infty,-7)\cup(11,\infty)$
- D$\text{x}\in(-\infty,-7)\cup[11,\infty)$
Solution:
$|\text{x}+2|\leq9$
$\Rightarrow-9\leq\text{x}+2\leq9$
$\Rightarrow-9-2\leq\text{x}+2-2\leq9-2$
$\Rightarrow-11\leq\text{x}\leq7$
$\Rightarrow\text{x}\in[-11,7]$
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