MCQ
Distinction in pentene$-1$ and pentyne$-1$ is done by
- ✓${[Ag{(N{H_3})_2}]^ + }$
- BConc. ${H_2}S{O_4}$
- C$HCl$
- D$B{r_2}$
✓
Answer
Correct option: A.
${[Ag{(N{H_3})_2}]^ + }$
a
$1$-Pentene does not react with Tollen's reagent.
$1$-Pentene does not react with Tollen's reagent.
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