MCQ
$\frac{1}{{\tan 3A - \tan A}} - \frac{1}{{\cot 3A - \cot A}} = $
  • A
    $\tan A$
  • B
    $\tan 2A$
  • C
    $\cot A$
  • $\cot 2A$

Answer

Correct option: D.
$\cot 2A$
d
(d) $\frac{1}{{\tan 3A - \tan A}} - \frac{1}{{\cot 3A - \cot A}}$

$=\frac{1}{{\tan 3A - \tan A}} + \frac{{\tan A\tan 3A}}{{\tan 3A - \tan A}}$

$= \frac{1}{{\tan 2A}} = \cot 2A$.

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