MCQ
$\frac{{\cos {{10}^o} + \sin {{10}^o}}}{{\cos {{10}^o} - \sin {{10}^o}}} = $
- ✓$\tan \,{55^o}$
- B$\cot {55^o}$
- C$ - \tan {35^o}$
- D$ - \cot {35^o}$
✓
Answer
Correct option: A.
$\tan \,{55^o}$
a
(a) $\frac{{\cos {{10}^o} + \sin {{10}^o}}}{{\cos {{10}^o} - \sin {{10}^o}}}$
(a) $\frac{{\cos {{10}^o} + \sin {{10}^o}}}{{\cos {{10}^o} - \sin {{10}^o}}}$
$ = \tan ({45^o} + {10^o}) = \tan {55^o}$.
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