Question
$\frac{{\cos 17^\circ + \sin 17^\circ }}{{\cos 17^\circ - \sin 17^\circ }} = $
$\frac{{\cos \,\,{{17}^o} + \sin \,\,{{17}^o}}}{{\cos \,\,{{17}^o} - \sin \,\,{{17}^o}}}$
$ = \frac{{1 + \tan \,\,{{17}^o}}}{{1 - \tan \,\,{{17}^o}}} $
$= \frac{{\tan \,\,{{45}^o} + \tan \,\,{{17}^o}}}{{1 - \tan \,\,{{45}^o}\tan \,\,{{17}^o}}} = \tan \,\,{62^o}$.
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$f(x)=\left\{\begin{array}{cc}x+1, & x < 0 \\|x-1|, & x \geq 0\end{array} \text { and } g(x)=\left\{\begin{array}{cc}x+1, & x < 0 \\1, & x \geq 0\end{array}\right. \text {. }\right.$
द्वारा परिभाषित हैं। तो $(gof) (x)$