MCQ
$\frac{d}{d x}\left(\cot ^{-1} x\right)=$
  • A
    $\frac{1}{1+x^2}$
  • B
    $\frac{1}{1+x}$
  • C
    $\frac{-1}{1+x}$
  • $\frac{-1}{1+x^2}$

Answer

Correct option: D.
$\frac{-1}{1+x^2}$
D

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