MCQ
$\frac{d}{d x}\left[\tan ^{-1} \sqrt{1+x^2}-\cot ^{-1}\left(-\sqrt{1+x^2}\right)\right]=$
  • A
    $\pi$
  • B
    1
  • $0$
  • D
    $\frac{2 x}{\sqrt{1+x^2}}$

Answer

Correct option: C.
$0$
C

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