Question
$\frac{d}{{dx}}\{ {(\sin x)^x}\} = $
$ \Rightarrow \frac{{dy}}{{dx}} = {(\sin x)^x}[x\cot x + {\log _e}\sin x]$
$ = {(\sin x)^x}\left[ {\frac{{x\cos x + \sin x\log \sin x}}{{\sin x}}} \right]$.
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