Question
$\frac{{\sin 70^\circ + \cos 40^\circ }}{{\cos 70^\circ + \sin 40^\circ }} = $
$ = \frac{{\sin 70^\circ + \sin 50^\circ }}{{\sin 20^\circ + \sin 40^\circ }} $
$= \frac{{2\sin 60^\circ \cos 10^\circ }}{{2\sin 30^\circ \cos ( - 10^\circ )}}$
$ = \frac{{\sin \,\,{{60}^o}}}{{\sin \,\,{{30}^o}}} = \frac{{\sqrt 3 }}{2}.\frac{2}{1} = \sqrt 3 $.
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