$B^2=\left[\begin{array}{cc}1 & -i \\ 0 & 1\end{array}\right]\left[\begin{array}{cc}1 & -i \\ 0 & 1\end{array}\right]=\left[\begin{array}{cc}1 & -2 i \\ 0 & 1\end{array}\right]$
$B ^3=\left[\begin{array}{cc}1 & -3 i \\ 0 & 1\end{array}\right]$
$B ^{2023}=\left[\begin{array}{cc}1 & -2023 i \\ 0 & 1\end{array}\right]$
$M = A ^{ T } BA$
$M ^2= M \cdot M = A ^{ T } BA A ^{ T } BA = A ^{ T } B ^2 A$
$M ^3= M ^2 \cdot M = A ^{ T } B ^2 A A ^{ T } BA = A ^{ T } B ^3 A$
$M ^{2023}=$ $A ^{ T } B ^{2023} A$
$AM ^{2023} A ^{ T }= AA ^{ T } B ^{2023} AA ^{ T }= B ^{2023}$
$=\left[\begin{array}{cc}1 & -2023 i \\ 0 & 1\end{array}\right]$
Inverse of $\left( AM ^{2023} A ^{ T }\right)$ is $\left[\begin{array}{cc}1 & 2023 i \\ 0 & 1\end{array}\right]$
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$f(x)=\left\{\begin{array}{cl}\frac{\sin \left(x^2\right)}{x} & \text { if } x \neq 0, \\
0 & \text { if } x=0\end{array}\right.$
तब $x=0$ पर $f$