MCQ
$\frac{{\sin {{81}^o} + \cos {{81}^o}}}{{\sin {{81}^o} - \cos {{81}^o}}}$ is equal to
  • A
    $cot9^o$
  • B
    $tan9^o$
  • C
    $cot54^o$
  • $tan54^o$

Answer

Correct option: D.
$tan54^o$
d
$E=\frac{1+tan\,9^o}{1-tan\,9^o} =tan\, 54^o$

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