Question
$\frac{\sqrt{32}+\sqrt{48}}{\sqrt{8}+\sqrt{12}}$ is equal to :
✓
Answer
- 2
Solution :
$\frac{\sqrt{32}+\sqrt{48}}{\sqrt{8}+\sqrt{12}}$
$\Rightarrow\frac{\sqrt{16\times2}+\sqrt{16\times3}}{\sqrt{4\times2}+\sqrt{4\times3}}$
$\Rightarrow\frac{4\sqrt{2}+4\sqrt{3}}{2\sqrt{2}+2\sqrt{3}}$
$\Rightarrow\frac{4}{2}(\frac{\sqrt{2}+\sqrt{3}}{\sqrt{2}+\sqrt{3}})$
$\Rightarrow2$
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