Question
In the adjoining figure, $\triangle\text{ABC}\cong\triangle\text{ADC}.$ If $\angle\text{BAC} = 30^\circ$ and $\angle\text{ABC} = 100^\circ$ then $\angle\text{ACD}$ is equal to:
✓
Answer
In triangle ABC, $\angle\text{BAC} = 30^\circ$ and $\angle\text{ABC} = 100^\circ ($Given$)$
$\angle\text{BAC} + \angle\text{ABC} + \angle\text{BCA} = 180^\circ$
$\angle\text{BAC} = 50^\circ$
Also $\angle\text{ACD} = 50^\circ($Since, $\triangle\text{ABC}\cong\triangle\text{ADC})$
$\angle\text{BAC} + \angle\text{ABC} + \angle\text{BCA} = 180^\circ$
$\angle\text{BAC} = 50^\circ$
Also $\angle\text{ACD} = 50^\circ($Since, $\triangle\text{ABC}\cong\triangle\text{ADC})$
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