Question
Divide $5 z^3-6 z^2+7 z$ by $2 z$
✓
Answer
$\frac{5\text{z}^3-6\text{z}^2+7\text{z}}{2\text{z}}$
$=\frac{5\text{z}^3}{2\text{z}}-\frac{6\text{z}^2}{2\text{z}}+\frac{7\text{z}}{2\text{z}}$
$=\frac{5}{2}\text{z}^{(3-1)}-3\text{z}^{(2-1)}+\frac{7}{2}$
$=\frac{5}{2}\text{z}^2-3\text{z}+\frac{7}{2}$
$=\frac{5\text{z}^3}{2\text{z}}-\frac{6\text{z}^2}{2\text{z}}+\frac{7\text{z}}{2\text{z}}$
$=\frac{5}{2}\text{z}^{(3-1)}-3\text{z}^{(2-1)}+\frac{7}{2}$
$=\frac{5}{2}\text{z}^2-3\text{z}+\frac{7}{2}$
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