Question
Divide $acx^2+ (bc + ad) x + bd$ by $(ax + b)$

Answer

$\frac{\text{acx}^2+(\text{bc}+\text{ad})\text{x}+\text{bd}}{\text{ax}+\text{b}}$
$=\frac{\text{acx}^2+\text{bcx}+\text{adx}+\text{bd}}{\text{ax}+\text{b}}$
$=\frac{\text{cx}(\text{ax}+\text{b})+\text{d}(\text{ax}+\text{b})}{\text{ax}+\text{b}}$
$=\frac{(\text{ax}+\text{b})(\text{cx}+\text{d)}}{\text{ax}+\text{b}}=\text{cx}+\text{d}$

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