Question
Solve the linear equation $x + 7 - \frac{{8x}}{3} = \frac{{17}}{6} - \frac{{5x}}{2}$
✓
Answer
$x + 7 - \frac{{8x}}{3} = \frac{{17}}{6} - \frac{{5x}}{2}$
It is a linear equation since it involves linear expressions only.
$\therefore$ $x - \frac{{8x}}{3} + \frac{{5x}}{2} = \frac{{17}}{6} - 7$ ... [Transposing $ - \frac{{5x}}{2}$ to $L.H.S.$ and $7$ to $R.H.S]$
$\therefore$ $\frac{{6x - 16x + 15x}}{6} = \frac{{17 - 42}}{6}$
$\therefore$ $\frac{{5x}}{6} = \frac{{ - 25}}{6}$
$\therefore$ $x = \frac{{ - 25}}{6} \times \frac{6}{5}$ ... [Multiplying both sides by $\frac{6}{5}$]
$\therefore x = -5$ this is the required solution.
It is a linear equation since it involves linear expressions only.
$\therefore$ $x - \frac{{8x}}{3} + \frac{{5x}}{2} = \frac{{17}}{6} - 7$ ... [Transposing $ - \frac{{5x}}{2}$ to $L.H.S.$ and $7$ to $R.H.S]$
$\therefore$ $\frac{{6x - 16x + 15x}}{6} = \frac{{17 - 42}}{6}$
$\therefore$ $\frac{{5x}}{6} = \frac{{ - 25}}{6}$
$\therefore$ $x = \frac{{ - 25}}{6} \times \frac{6}{5}$ ... [Multiplying both sides by $\frac{6}{5}$]
$\therefore x = -5$ this is the required solution.
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