Question
Divide first polynomial by second polynomial and write the answer in the form ‘Dividend = Divisor x Quotient + Remainder’ :
$x^3 – 64; x – 4$
$x^3 – 64; x – 4$
✓
Answer
$x^3 – 64 = x3 + 0x^2 + 0x – 64$
$\therefore$ Quotient = $x^2 + 4x + 16$, Remainder = $0$
Now, Dividend = Divisor x Quotient + Remainder
$\therefore x^3 – 64 = (x – 4)(x^2 + 4x + 16) + 0$
$\therefore$ Quotient = $x^2 + 4x + 16$, Remainder = $0$
Now, Dividend = Divisor x Quotient + Remainder
$\therefore x^3 – 64 = (x – 4)(x^2 + 4x + 16) + 0$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Find the area of a triangle two sides of which are 18cm and 10cm and the perimeter is 42cm.
Rationalise the denominator of the following:$\frac{3}{\sqrt{3}+\sqrt{5}-\sqrt{2}}$
→If $\text{a}=\frac{\sqrt{3}-\sqrt{2}}{\sqrt{3}+\sqrt{2}}$ and $\text{b}=\frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}-\sqrt{2}},$ find the value of $a^2 + b^2 - 5ab.$
→O is the circumference of the triangle ABC and OD is perpendicular on BC. Prove that $\angle\text{BOD}=\angle\text{A}.$
→In the adjoining figure, the point D divides the side BC of $\triangle\text{ABC}$ in the ratio m : n. Prove that $\text{ar}(\triangle\text{ABD}):\text{ar}(\triangle\text{ADC})=\text{m}:\text{n}$
→Draw a line segment AB and by ruler and compasses, obtain a line segment of length $\frac{3}{4}\text{(AB)}.$
→In a rhombus PQRS, if PQ = 7.5 cm, then find QR. If ∠QPS 75°, then find the measures of ∠PQR and ∠SRQ.
Find the area of a rhombus whose perimeter is 80m and one of whose diagonal is $24m.$
→In $\triangle\text{PQR},$ if $\angle\text{P}-\angle\text{Q}=42^\circ$ and $\angle\text{Q}+\angle\text{R}=21^\circ,$ find $\angle\text{P},\angle\text{Q}$ and $\angle\text{R}.$
→Simplify $\Big[\Big\{(625)^{\frac{1}{2}}\Big\}^{-\frac{1}{4}}\Big]^2$
→