Question
Divide $x^4-y^4$ by $x^2-y^2$
✓
Answer
$\frac{\text{x}^4-\text{y}^4}{\text{y}^2-\text{y}^2}$
$=\frac{\big(\text{x}^2\big)^2-\big(\text{y}^2\big)^2}{\big(\text{x}^2-\text{y}^2\big)}$
$=\frac{\big(\text{x}^2-\text{y}^2\big)\times\big(\text{x}^2+\text{y}^2\big)}{\big(\text{x}^2-\text{y}^2\big)}=\text{x}^2+\text{y}^2$
$=\frac{\big(\text{x}^2\big)^2-\big(\text{y}^2\big)^2}{\big(\text{x}^2-\text{y}^2\big)}$
$=\frac{\big(\text{x}^2-\text{y}^2\big)\times\big(\text{x}^2+\text{y}^2\big)}{\big(\text{x}^2-\text{y}^2\big)}=\text{x}^2+\text{y}^2$
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