Question
Divide $x^4-y^4$ by $x^2-y^2$
✓
Answer
$\frac{x^4-y^4}{y^2-y^2}$
$=\frac{\left(x^2\right)^2-\left(y^2\right)^2}{\left(x^2-y^2\right)}$
$=\frac{\left(x^2-y^2\right) \times\left(x^2+y^2\right)}{\left(x^2-y^2\right)}=x^2+y^2$
$=\frac{\left(x^2\right)^2-\left(y^2\right)^2}{\left(x^2-y^2\right)}$
$=\frac{\left(x^2-y^2\right) \times\left(x^2+y^2\right)}{\left(x^2-y^2\right)}=x^2+y^2$
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