$(A)\xrightarrow[{\begin{array}{*{20}{c}}
{(2){\kern 1pt} A{g_2}O/{H_2}O} \\
{(3){\kern 1pt} \Delta }
\end{array}}]{{(1){\kern 1pt} \,excess\,{\kern 1pt} C{H_3}I/{K_2}C{O_3}}}(B)$ $\xrightarrow[{(iii){\kern 1pt} \Delta }]{{\begin{array}{*{20}{c}}
{(i){\kern 1pt} excess{\kern 1pt} C{H_3}I/{K_2}C{O_3}} \\
{(ii){\kern 1pt} A{g_2}O}
\end{array}}}$ $\begin{array}{*{20}{c}}
{{H_2}C = CH - CH - CH = C{H_2}} \\
{|{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} } \,\,\,\,\\
{{\mkern 1mu} {\mkern 1mu} C{H_3}}
\end{array}$
{(2){\kern 1pt} A{g_2}O/{H_2}O} \\
{(3){\kern 1pt} \Delta }
\end{array}}]{{(1){\kern 1pt} \,excess\,{\kern 1pt} C{H_3}I/{K_2}C{O_3}}}(B)$ $\xrightarrow[{(iii){\kern 1pt} \Delta }]{{\begin{array}{*{20}{c}}
{(i){\kern 1pt} excess{\kern 1pt} C{H_3}I/{K_2}C{O_3}} \\
{(ii){\kern 1pt} A{g_2}O}
\end{array}}}$ $\begin{array}{*{20}{c}}
{{H_2}C = CH - CH - CH = C{H_2}} \\
{|{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} } \,\,\,\,\\
{{\mkern 1mu} {\mkern 1mu} C{H_3}}
\end{array}$
Identify $A$
- A
- B
- C
- D
Medium
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1In amines, the hybridisation state of $N$ isView Solution
- 2View SolutionWhat will be the major product in the following mononitration reaction ?
- 3The total number of $\mathrm{sp}^2$ hybridised carbon atoms in the major product $P$ (a non-heterocyclic compound) of the following reaction is. . . . . . .View Solution
- 4Indentify the reagents $S$ and $\mu$ in the scheme below in which $R$ is converted to the nitrite $V$ via the benzylic halide $T.$View Solution
$R, S$ and $\mu$ respectively are
- 5View SolutionWhich of the following is expected to be the least basic ?
- 6View SolutionCompound that will give positive Lassaigne's test for both nitrogen and halogen is
- 7View SolutionFor the given reaction major product will be
Major product
- 8View SolutionAcetamide changes into methylamine by
- 9View SolutionHinsberg’s reagent is
- 10The structure of products $E -H,$ respectively areView Solution
