{{{(C{H_3})}_2}C.C{H_2}.CO.C{H_3}} \\
{\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,\,\,N{H_2}\,\,\,\,\,\,\,}
\end{array}$ is
- ADiacetone
- BAcetonamine
- ✓Diacetonamine
- DAminoacetone
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$(A)$Covalent radius decreases down the group from $\mathrm{C}$ to $\mathrm{Pb}$ in a regular manner.
$(B)$ Electronegativity decreases from $\mathrm{C}$ to $\mathrm{Pb}$ down the group gradually.
$(C)$ Maximum covalence of $\mathrm{C}$ is $4$ whereas other elements can expand their covalence due to presence of $d$ orbitals.
$(D)$ Heavier elements do not form $\mathrm{p} \pi-p \pi$ bonds.
$(E)$ Carbon can exhibit negative oxidation states.
Choose the correct answer from the options given below:

$\left[\right.$ Given $: \mathrm{h}=6.63 \times 10^{-34} \,\mathrm{Js}$ and $\left.\mathrm{c}=3.0 \times 10^{8} \,\mathrm{~ms}^{-1}\right]$
$2S{O_2} + {O_2}$ $\rightleftharpoons$ $2S{O_3};\,\,\Delta H = - 45.2\,kcal$ Which of the following factors favours the formation of $S{O_3}$