$\begin{matrix}
   O\,\,\,\,\,\,  \\
   ||\,\,\,\,\,\,  \\
   R-C-N{{H}_{2}}  \\
\end{matrix}$ $+xNaOH+B{{r}_{2}}\to $ $R-N{{H}_{2}}+2NaBr$ $+N{{a}_{2}}C{{O}_{3}}+{{H}_{2}}O$

Number of moles of $NaOH $ used in above Hoffmann bromamide reaction is

  • A$3$
  • B$4$
  • C$5$
  • D$6$
Medium
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