Question
Draw a line segment $CD.$ Produce it to $CE$ such that $CE = 3CD.$
✓
Answer
We draw a line $l$ and take two points $C$ and $D$ on it.
Take a divider and open it such that its end of both arms is at $C$ and $D.$
Then, we lift the divider and place its one end at $D$ and other end on the line $l$ opposite to $C$ as shown in the figure.
Let this point be $A.$
Lift the divider again and place its one end at $A$ and other end on the line $1$ opposite to $C.$
Name this point as $E.$
Here $CD = DE = AE$
Therefore, $CE = CD + DE + AE$
$= CD + CD + CD ($As, $CD ± DE = AE)$
or, $CE = 3CD$
Take a divider and open it such that its end of both arms is at $C$ and $D.$
Then, we lift the divider and place its one end at $D$ and other end on the line $l$ opposite to $C$ as shown in the figure.
Let this point be $A.$
Lift the divider again and place its one end at $A$ and other end on the line $1$ opposite to $C.$
Name this point as $E.$
Here $CD = DE = AE$
Therefore, $CE = CD + DE + AE$
$= CD + CD + CD ($As, $CD ± DE = AE)$
or, $CE = 3CD$
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