Question
Draw a line segment of length $\sqrt{3} \mathrm{~cm}$.
✓
Answer
Construct a right angled $\triangle \mathrm{OAB}$, in which
$\angle A=90^{\circ}, \text{OB}=2 \mathrm{~cm}$ and $\text{AB}=1 \mathrm{~cm}$
Using $\text{OA}^2+\text{AB}^2=\text{OB}^2$
we get: $\text{OA}=\sqrt{3} \mathrm{~cm}$
$\angle A=90^{\circ}, \text{OB}=2 \mathrm{~cm}$ and $\text{AB}=1 \mathrm{~cm}$
Using $\text{OA}^2+\text{AB}^2=\text{OB}^2$
we get: $\text{OA}=\sqrt{3} \mathrm{~cm}$
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