Question
Draw a parallelogram $ABCD$, with $AB = 6 \ cm, AD = 4.8 \ cm$ and $\angle DAB = 45^\circ $. Draw the perpendicular bisector of side $AD$ and let it meet $AD$ at point $P$. Also, draw the diagonals $AC$ and $BD$; and let them intersect at point $O$. Join $O$ and $P$. Measure $OP.$

Answer


Steps :
  1. Draw $AB = 6 \ cm.$
  2. Draw $\angle PAB = 45^\circ .$
  3. Cut $AD = 4.8 \ cm.$
  4. From $D$, draw an arc of radius $6 \ cm.$
  5. From $B$, draw an arc of radius $4.8 \ cm$ which meets the first arc at $C.$
  6. Join $BC, CD, AD.$
    Thus $ABCD$ is the required $||\ gm.$
  7. Draw perpendicular bisector $XY$ of $AD$ which cuts $AD$ at $P.$
  8. Join $AC$ and $BD$ which intersect at $O.$
  9. Join $OP$ and measure it. $OP = 3 \ cm.$

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