Question
Draw a right angle and construct its bisector.
✓
Answer
$i.\ $Draw $OQ$ of any length.
$ii.\ $Place the centre of the protractor at $O$ and the zero edge along $OQ.$
$iii.\ $Start with $0$ near $Q.$ Mark point $P$ at $90^\circ .$
$iv.\ $Join $\overline{OP}$. Then, $\angle POQ = 90^\circ .$
$v.\ $With $O$ as centre and using compasses, draw an arc that cuts both rays of $\angle POQ$. Label the points of intersection as $P'$ and $Q'.$
$vi.\ $With $Q'$ as centre, draw $($in the interior of $\angle POQ)$ an arc whose radius is more than half the length $Q'P'.$
$vii.\ $With the same radius and with $P'$ as centre, draw another arc in the interior of $\angle POQ.$ Let the two arcs intersect at $R$. Then, $\overline{OR}$ is the bisector of $\angle POQ.$
$ii.\ $Place the centre of the protractor at $O$ and the zero edge along $OQ.$
$iii.\ $Start with $0$ near $Q.$ Mark point $P$ at $90^\circ .$
$iv.\ $Join $\overline{OP}$. Then, $\angle POQ = 90^\circ .$
$v.\ $With $O$ as centre and using compasses, draw an arc that cuts both rays of $\angle POQ$. Label the points of intersection as $P'$ and $Q'.$
$vi.\ $With $Q'$ as centre, draw $($in the interior of $\angle POQ)$ an arc whose radius is more than half the length $Q'P'.$
$vii.\ $With the same radius and with $P'$ as centre, draw another arc in the interior of $\angle POQ.$ Let the two arcs intersect at $R$. Then, $\overline{OR}$ is the bisector of $\angle POQ.$
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