Question
Draw a triangle ABC with AB = 3cm, BC = 4cm and $\angle\text{B}=60^\circ.$ Also, draw the bisector of angles C and A of the triangle, meeting in a point O. Measure $\angle\text{COA}.$
✓
Answer
Steps of construction:
Step I: Draw a line segment BC = 4cm.
Step II: Draw $\angle\text{CBX}=60^\circ.$
Step III: Draw an arc on BX at a radius of 3cm cutting BX at A.
Step IV: Join AC to get the required triangle.
Angle bisector for angle A:
Step I: With A as centre, cut arcs of the same radius cutting AB and AC at P and Q, respectively.
Step II: From P and Q cut arcs of same radius intersecting at R.
Step II: Join AR to get the angle bisector of angle A.
Angle bisector for angle C:
Step I: With A as centre, cut arcs of the same radius cutting CB and CA at M and N, respectively.
Step II: From M and N, cut arcs of the same radius intersecting at T
Step III: Join CT to get the angle bisector of angle C.
Step IV: Mark the point of intersection of CT and AR as 0.
Step V: Angle $\angle\text{COA}=120^\circ.$
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