Question
Construct a $\triangle\text{ABC}$ in which BC = 3.6cm, AB = 5cm and AC = 5.4cm. Draw the perpendicular bisector of the side BC.
✓
Answer
Steps for construction:
Step I: Draw a line segment (AB) of length 5cm.
Step II: Draw an arc of radius 5.4cm from the centre (A).
Step III: With B as the centre, draw another arc of radius 3.6cm, cutting the previous arc at C.
Step IV: Join AC and BC.
Step V: Taking B as the centre and the radius more than half of BC, draw two arcs on both the sides of BC.
Step VI: Similarly, taking C as the centre and the same radius, draw arcs on both the sides of BC, cutting the previous arcs at P and Q.
Then, PQ is the required perpendicuar bisector of BC, meeting BC at D.
Step I: Draw a line segment (AB) of length 5cm.
Step II: Draw an arc of radius 5.4cm from the centre (A).
Step III: With B as the centre, draw another arc of radius 3.6cm, cutting the previous arc at C.
Step IV: Join AC and BC.
Step V: Taking B as the centre and the radius more than half of BC, draw two arcs on both the sides of BC.
Step VI: Similarly, taking C as the centre and the same radius, draw arcs on both the sides of BC, cutting the previous arcs at P and Q.
Then, PQ is the required perpendicuar bisector of BC, meeting BC at D.
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