Question
Draw molecular orbital energy level diagram for $\text{N}^+_2.$ Calculate its bond order and explain its magnetic characteristics.
✓
Answer
$\text{N}^+_2(13):\sigma\text{ls}^2,\sigma\text{*ls}^2,\sigma2\text{s}^2,\sigma*2\text{s}^2,\pi2\text{p}^2_\text{x}=\pi2\text{p}^2_\text{y},\sigma2\text{p}^1_\text{z}$
$\text{B.O.}=\frac12(9-4)=\frac52=2.5$
It is paramagnetic due to presence of one unpaired electron.
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