Question
Why does $\text{SO}_3$ act as an electrophile?
✓
Answer
Three highly electronegative oxygen atoms are attached to sulphur atom. This makes sulphur atom electron deficient. Due to resonance, sulphur also acquires positive charge. Both these factors make $\text{SO}_3$ an electrophile.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Compound with carbon-carbon double bond, such as ethylene ($\text{C}_2\text{H}_4$) and hydrogen in a reaction is called hydrogenation.$\text{C}_2\text{H}_4(\text{g})+\text{H}_2(\text{g})\overrightarrow{\ \ \ \ \ \ }\ \text{C}_2\text{H}_6(\text{g})$
Calculate enthalpy change for the reaction using the following combustion data:$\text{C}_2\text{H}_4(\text{g})+3\text{O}_2(\text{g})\overrightarrow{\ \ \ \ \ }\ 2\text{CO}_2(\text{g})+2\text{H}_2\text{O(g)};$ $\Delta\text{H}=-1401\text{kJ/ mol}$
$\text{C}_2\text{H}_6(\text{g})+\frac{7}{2}\text{O}_2(\text{g})\overrightarrow{\ \ \ \ \ \ }\ 2\text{CO}_2(\text{g})+3\text{H}_2\text{O(l)};$ $\Delta\text{H}=-1550\text{kJ/ mol}$
$\text{H}_2(\text{g})+\frac{1}{2}\text{O}_2(\text{g})\overrightarrow{\ \ \ \ \ \ }\ \text{H}_2\text{O(l)};$ $\Delta\text{H}=-286.0\text{kJ/ mol}$
→Calculate enthalpy change for the reaction using the following combustion data:$\text{C}_2\text{H}_4(\text{g})+3\text{O}_2(\text{g})\overrightarrow{\ \ \ \ \ }\ 2\text{CO}_2(\text{g})+2\text{H}_2\text{O(g)};$ $\Delta\text{H}=-1401\text{kJ/ mol}$
$\text{C}_2\text{H}_6(\text{g})+\frac{7}{2}\text{O}_2(\text{g})\overrightarrow{\ \ \ \ \ \ }\ 2\text{CO}_2(\text{g})+3\text{H}_2\text{O(l)};$ $\Delta\text{H}=-1550\text{kJ/ mol}$
$\text{H}_2(\text{g})+\frac{1}{2}\text{O}_2(\text{g})\overrightarrow{\ \ \ \ \ \ }\ \text{H}_2\text{O(l)};$ $\Delta\text{H}=-286.0\text{kJ/ mol}$
Knowing the properties of $\mathrm{H}_2 \mathrm{O}$ and $\mathrm{D}_2 \mathrm{O}$, do you think that $\mathrm{D}_2 \mathrm{O}$ can be used for drinking purposes?
→For a hydrogen like particle, derive the expression,
$\text{v}_\text{n}=\Big(\frac{\text{Ze}^2}{\text{mr}_\text{n}}\Big)^\frac{1}{2}$
Where vn is the velocity of the electron at distance rn from the nucleus, Z is the atomic number of the H-like particle, e and m are the charge and mass of the electron.
→$\text{v}_\text{n}=\Big(\frac{\text{Ze}^2}{\text{mr}_\text{n}}\Big)^\frac{1}{2}$
Where vn is the velocity of the electron at distance rn from the nucleus, Z is the atomic number of the H-like particle, e and m are the charge and mass of the electron.
Calculate the number of gram molecules of water in a beaker containing 576g of water.
What happens when $\text{Cu}^{2+}$ is added KI solution? Indicator used in this titration?
→Element Aburns in nitrogen to give an ionic compound B. Compound B reacts with water to give C and D. A solution of C becomes milky on bubbling carbon dioxide. Identify A, B, C and D.
Calculate the free energy change when 1 mole of NaCl is dissolved in water at 298 K . (Given, lattice energy of $\mathrm{NaCl}=$ $-777.8 \mathrm{~kJ} \mathrm{~mol}^{-1}$, hydration energy $=-774.1 \mathrm{~kJ} \mathrm{~mol}^{-1}$ and $\Delta \mathrm{S}=0.043 \mathrm{~kJ} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$ at 298 K ).
→Why does rain water normally have a pH of 5.6? When does it become acid rain?
Element A reacts with aqueous NaOH solution to form B and H . Aqueous solution of B is hetated to $323-33 \mathrm{~K}$ and on passing $\mathrm{CO}_2$ into it, $\mathrm{Na}_2 \mathrm{CO}_3$ and C were formed. When C is heated to $1200^{\circ} \mathrm{C}, \mathrm{Al}_2 \mathrm{O}_3$ is formed. identify A,B, and C and also write the reaction involved.
→(a) How will you obtain Gamaxene from benzene.
(b) Name any two carcinogenic hydrocarbons.
(b) Name any two carcinogenic hydrocarbons.