Question
Draw the graph of the following linear equations in two variables:
2y = -x + 1
2y = -x + 1
✓
Answer
We have, 2y = -x + 1⇒ x = 1 - 2y ...(i)
Putting y = 0, we get x = 1 - 2 × 0 = 1 Putting y = -1 we get x = 1 - 2(-1) = 3 Thus, we have the following table giving two points on the line represented by the equation 2y = -x + 1: Graph of the equation 2y = -x + 1:
Putting y = 0, we get x = 1 - 2 × 0 = 1 Putting y = -1 we get x = 1 - 2(-1) = 3 Thus, we have the following table giving two points on the line represented by the equation 2y = -x + 1: Graph of the equation 2y = -x + 1:
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In a triangle $\triangle\text{ABC},$ AB = 15cm, BC = 13cm and AC = 14cm. Find the area of triangle ABC and hence its altitude on AC.
→If $\text{x}-\frac{1}{\text{x}}=3+2\sqrt2,$ find the value of $\text{x}^3-\frac{1}{\text{x}^3}.$
→If $\text{x}-\frac{1}{\text{x}}=5,$ find the value of $\text{x}^3-\frac{1}{\text{x}^3}.$
→In the given figure, line RP || line MS and line DK is their transversal. ∠DHP = 85°. Find the measures of following angles.
i. ∠RHD
ii. ∠PHG
iii. ∠HGS
iv. ∠MGK
If measures opposite angles of a parallelogram are (60 - x)° and (3x - 4)°, then find the measures of angles of the parallelogram.
In the given figure, BA || ED and BC || EF. Show that $\angle\text{ABC}=\angle\text{DEF}.$
→Using factor theorem, factorize the following polynomials:
$3x^3 - x^2 - 3x + 1$
→$3x^3 - x^2 - 3x + 1$
If V is the volume of a cuboid of dimensions a, b, c and S is its surface area, then prove that:$\frac{1}{\text{V}}=\frac{2}{\text{S}}\Big(\frac{1}{\text{a}}+\frac{1}{\text{b}}+\frac{1}{\text{c}}\Big)$
→What is the difference between a theorem and an axiom?
If $\text{a}=\frac{\sqrt{5}+\sqrt{2}}{\sqrt{5}-\sqrt{2}}$ and $\text{b}=\frac{\sqrt{5}-\sqrt{2}}{\sqrt{5}+\sqrt{2}},$ show that $3\text{a}^2+4\text{ab}-3\text{b}^2=4+\frac{56}{3}\sqrt{10}.$
→