Chemical Bonding and Molecular Structure — Chemistry STD 11 Science — Question

$\text{Li(s)}+\frac{1}{2}\text{F}_2(\text{g})\overrightarrow{\ \ \ \ \ \ \ }\ \text{LiF(s)}$

$\text{Li(s)}\overrightarrow{\ \ \ \ \ \ \ \ }\ \text{Li(g)};$ $\Delta_\text{s}\text{H}^\circ=155\text{kJ mol}^{-1}$

$\frac{1}{2}\text{F}_2(\text{g})\overrightarrow{\ \ \ \ \ \ \ }\ \text{F(g)};$ $\Delta\text{H}^\circ=75\text{kJ}$

$\text{Li(g)}\overrightarrow{\ \ \ \ \ } \ \text{Li}^{+}(\text{g})+\text{e}^-;$ $\Delta\text{H}^\circ=520\text{kJ mol}^{-1}$

$\text{F(g)}+\text{e}^-\overrightarrow{\ \ \ \ \ \ } \ \text{F}^-(\text{g});$ $\Delta\text{H}^\circ=-333\text{kJ mol}^{-1}$

$\text{Li}^+\text{(g)}+\text{F}^-(\text{g})\overrightarrow{\ \ \ \ \ \ \ \ }\ \text{LiF(s)};$ $\Delta\text{H}^\circ=-1012\text{kJ mol}^{-1}$