Question
During the thermodynamic process shown in figure for an ideal gas
✓
Answer
(d)
For a straight $P-V$ graph line $P \propto V$
If pressure increases, volume increases then $T$ also increases $[P V \propto T]$
So $\Delta T \neq 0$
Volume increasing so work is positive, $W > 0$
and temperature also increasing so $\Delta Q > 0$
$\because \Delta Q=\Delta U+\Delta W$
So $\Delta U > 0$
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