MCQ
$EDTA$ has coordination number
- A$3$
- B$4$
- C$5$
- ✓$6$

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| List$-I$ | List$-II$ |
| $(a)$ $\left[ Co \left( NH _{3}\right)_{6}\right]\left[ Cr ( CN )_{6}\right]$ |
$(i)$ Linkage isomerism |
| $(b)$ $\left[ Co \left( NH _{3}\right)_{3}\left( NO _{2}\right)_{3}\right]$ |
$(ii)$Solvate isomerism |
| $(c)$ $\left[ Cr \left( H _{2} O \right)_{6}\right] Cl _{3}$ |
$(iii)$ Co-ordination isomerism |
| $(c)$ $cis-[CrCl$ $\left._{2}(\text { ox })_{2}\right]^{3-}$ | $(iv)$ Optical isomerism |
Choose the correct answer from the options given below:
$MnO_4^ - + 5F{e^{2 + }} + 8{H^ + } \to M{n^{2 + }} + 5F{e^{3 + }} + 4{H_2}O$
Here $10\,ml$ of $0.1\,M$ $KMn{O_4}$ is equivalent to