If \(\mathrm{Fe}^{3+} / \mathrm{Fe}^{2+}(=+0.77 \mathrm{V})\) is greater than that of \(I_{2} / 2 \mathrm{I}^{-}(=0.536 \mathrm{V}),\) Fe \(^{3+}\) will be reduced to \(\mathrm{Fe}^{2+}\) and \(I^-\) will be oxidised to \(I_2\).
$E^oFe^{3+}_{(aq)} + e^{-} \rightarrow Fe^{2+}_{(aq)}$ કેટલા ............ $\mathrm{V}$ થાય?
$Fe^{3+}\,\,_{(aq)} + 3e^{-} \rightarrow Fe_{(s)}$ ; $E^o = -0.036 \,volt; $
$Fe^{2+}_{(aq)} + 2e^{-} \rightarrow Fe_{(s)}$ ; $E^o = -0.440 \,volt$
આપેલ :
$F{e^{2 + }} + 2{e^ - } \to Fe;$ ${E^o}_{F{e^{2 + }}/Fe} = - 0.47\,V$
$F{e^{3 + }} + {e^ - } \to F{e^{2 + }};$ ${E^o}_{F{e^{3 + }}/F{e^{2 + }}} = + 0.77\,V$
($Cu$ નું આણ્વિય દળ $63\,u$)
${Zn}({s})+{Cu}^{2+}(0.02 {M}) \rightarrow {Zn}^{2+}(0.04 {M})+{Cu}({s})$
${E}_{\text {cell }}=...... \,\times 10^{-2} \,{~V}$ { (નજીકના પૂર્ણાંકમાં) }
${\left[ {E}_{{Cu} / {Cu}^{2+}}^{0}=-0.34\, {~V}, {E}_{2 {n} / {Zn}^{2+}}^{0}=+0.76 \,{~V}\right.}$
$\left.\frac{2.303 {RT}}{{F}}=0.059\, {~V}\right]$
$(i)$ $Zn| Zn^{2+} {(1\,M)}|| Cu^{2+}{(0.1\,M)}| Cu$
$(ii)$ $Zn| Zn^{2+} {(1\,M)}|| Cu^{2+}(1\,M) |Cu $
$(iii)$ $Zn| Zn^{2+} {(0.1\,M)}|| Cu^{2+}{(1\,M)}| Cu$