$\therefore$ Moles of carbon

$=\left(\text { Moles of } CO _2\right) \times 1$

$=\frac{1}{200}$

$\therefore$ wt. of $C =\frac{1}{200} \times 12=0.06$

$\text { \% of } C =\frac{0.06}{ W } \times 100=24$

$( W = Wt \text {. of Organic Compound })$

$W =0.25$

Moles of $H _2 O =\frac{0.126}{18}=0.007$

$\therefore \text { Moles of } H \text { atom }=2 \times 0.007=0.014$

$\%$ of Hydrogen $=\frac{0.014 \times 1}{ W } \times 100$

$=\frac{0.014 \times 1}{0.25} \times 100$

$=5.6$

$=56 \times 10^{-1}$