d
(d)

\(T=40 \,s\)

If \(t=2\) minute \(20\) second

\(=2 \times 60+20\)

\(=140 \,s\)

So, it has completed \(3 \frac{1}{2}\) revolution.

Distance travelled \(=3 \times 2 \pi R+\pi R\) \(=7 \pi R\)

Displacement \(=2 R\)

\(\frac{\mid \text { Displacement| }}{\text { Distance }}=\frac{2 R}{7 \pi R}=\frac{2}{7 \times \frac{22}{7}}=\frac{1}{11}\)