Distance of a point from the wire, \(r=20 \,cm =0.2 \,m\)

Magnitude of the magnetic field at this point is given as:

\(B=\frac{\mu_{0}}{4 \pi} \frac{2 I}{r}\)

Where,

\(\mu_{0}=\) Permeability of free space \(=4 \pi \times 10^{-7} \,T\,m\, A ^{-1}\)

\(B=\frac{4 \pi \times 10^{-7} \times 2 \times 35}{4 \pi \times 0.2}\)

\(=3.5 \times 10^{-5} \;T\)

Hence, the magnitude of the magnetic field at a point \(20\, cm\) from is \(3.5 \times 10^{-5} \;T\)