\( = 200 \times {10^6} \times 1.6 \times {10^{ - 19}}J = 3.2 \times {10^{ - 11}}J\)
\(P = 16\,KW = 16 \times {10^3}Watt\)
Now, number of nuclei required per second
\(n = \frac{P}{E} = \frac{{16 \times {{10}^3}}}{{3.2 \times {{10}^{ - 11}}}} = 5 \times {10^{14}}\).