b
Here \(z\)-axis is vertically upward means normal to plane of paper as shown in figure.

Thus, \(\vec{A}=A \hat{k}\) and \(\vec{B}=B \hat{j}\)

So, \(\overrightarrow{ A } \times \overrightarrow{ B }= A \hat{ k } \times \overrightarrow{ Bj }=- AB \hat{ i }\)

Thus, it is along negative \(x\)-axis means along west.